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Showing posts with label Surveying. Show all posts
Showing posts with label Surveying. Show all posts

Friday, August 21, 2026

Surveying Instruments & Their Uses – 50 MCQs | Civil Engineering

Surveying Instruments & Their Uses – 50 MCQs | Civil Engineering

Surveying Instruments & Their Uses

Important Surveying Devices + 50 MCQs for Civil Engineering Exams

Surveying Instruments – Introduction

Surveying เคฎें เค…เคฒเค—-เค…เคฒเค— instruments เค•ा เค‰เคชเคฏोเค— distance, angle, elevation, bearing, coordinates, slope เคคเคฅा contour information determine เค•เคฐเคจे เค•े เคฒिเค เค•िเคฏा เคœाเคคा เคนै। เคจीเคšे Civil Engineering competitive examinations เค•े เคฒिเค important surveying devices เค”เคฐ เค‰เคจเค•े uses เคฆिเค เค—เค เคนैं।

Exam Tip: เค•ेเคตเคฒ instrument เค•ा เคจाเคฎ เคฏाเคฆ เคจ เค•เคฐें। เคฏเคน เคญी เคฏाเคฆ เคฐเค–ें เค•ि instrument เค•िเคธ quantity เค•ो measure เค•เคฐเคคा เคนै เค”เคฐ เค‰เคธเค•ा primary use เค•्เคฏा เคนै।
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1. Chain Surveying Instruments

Chain

Use: Horizontal distance measurement.

Important: Metric chains commonly 20 m เคฏा 30 m เค•ी เคนोเคคी เคนैं।

Steel Tape

Use: Accurate linear distance measurement.

Ranging Rod

Use: Survey lines เค•ो range เค•เคฐเคจे เค”เคฐ points mark เค•เคฐเคจे เค•े เคฒिเค।

Arrows

Use: Chain lengths เค•ी counting เค”เคฐ chain position marking.

Survey Peg

Use: Survey stations เค•ो ground เคชเคฐ mark เค•เคฐเคจे เค•े เคฒिเค।

Cross Staff

Use: Chain line เคธे perpendicular offset เคฒेเคจे เค•े เคฒिเค।

Optical Square

Use: 90° perpendicular offset establish เค•เคฐเคจे เค•े เคฒिเค।

Line Ranger

Use: เคฆो points เค•े เคฌीเคš intermediate point เค•ो range เค•เคฐเคจे เค•े เคฒिเค।

2. Compass Surveying Instruments

Prismatic Compass

Use: Magnetic bearings เค”เคฐ horizontal directions measure เค•เคฐเคจे เค•े เคฒिเค।

Bearing System: Whole Circle Bearing.

Surveyor's Compass

Use: Magnetic bearings measure เค•เคฐเคจे เค•े เคฒिเค।

Bearing System: Quadrantal Bearing.

Trough Compass

Use: Plane table เค•ो magnetic north เค•े เค…เคจुเคธाเคฐ orient เค•เคฐเคจे เค•े เคฒिเค।

3. Plane Table Surveying Instruments

Plane Table

Use: Field observation เค”เคฐ plotting simultaneously เค•เคฐเคจे เค•े เคฒिเค।

Alidade

Use: Sighting เค”เคฐ direction lines draw เค•เคฐเคจे เค•े เคฒिเค।

Plumbing Fork

Use: Plane table เค•ो station เค•े เค ीเค• เคŠเคชเคฐ centre เค•เคฐเคจे เค•े เคฒिเค।

Spirit Level

Use: Plane table เค•ो horizontal เค•เคฐเคจे เค•े เคฒिเค।

4. Levelling Instruments

Dumpy Level

Use: Difference in elevation เค”เคฐ reduced levels determine เค•เคฐเคจे เค•े เคฒिเค।

Tilting Level

Use: Line of sight เค•ो horizontal เค•เคฐเคจे เค•े เคฒिเค telescope เค•ो tilt เค•िเคฏा เคœा เคธเค•เคคा เคนै।

Auto Level

Use: Automatic compensator เค•ी เคธเคนाเคฏเคคा เคธे horizontal line of sight establish เค•เคฐเคจे เค•े เคฒिเค।

Digital Level

Use: Electronic staff readings เคฆ्เคตाเคฐा accurate levelling.

Levelling Staff

Use: Level เคธे readings เคฒेเค•เคฐ elevation difference determine เค•เคฐเคจा।

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5. Theodolite Instruments

Theodolite

Use: Horizontal เคคเคฅा vertical angles accurately measure เค•เคฐเคจे เค•े เคฒिเค।

Transit Theodolite

Use: Telescope เค•ो vertical plane เคฎें 180° transit เค•เคฐเคจे เค•े เคฒिเค।

Electronic Theodolite

Use: Angles เค•ो electronically measure เค”เคฐ display เค•เคฐเคจे เค•े เคฒिเค।

6. Modern Surveying Instruments

Total Station

Use: Horizontal angle, vertical angle เค”เคฐ slope distance measure เค•เคฐเค•े coordinates determine เค•เคฐเคจा।

EDM

Use: Electromagnetic waves เค•ी เคธเคนाเคฏเคคा เคธे distance measurement.

GPS / GNSS Receiver

Use: Satellite signals เคธे position เค”เคฐ coordinates determine เค•เคฐเคจा।

DGPS

Use: Differential corrections เคธे positioning accuracy improve เค•เคฐเคจा।

Laser Distance Meter

Use: Laser beam เคธे distance measurement.

Laser Level

Use: Horizontal เคฏा vertical reference line establish เค•เคฐเคจा।

LiDAR

Use: Laser pulses เคธे detailed 3D surface/terrain data collect เค•เคฐเคจा।

Drone Survey

Use: Aerial mapping เค”เคฐ photogrammetric survey.

Photogrammetry

Use: Photographs เคธे measurements เค”เคฐ maps เคคैเคฏाเคฐ เค•เคฐเคจा।

7. Slope Measurement Instruments

Abney Level

Use: Slope เค”เคฐ vertical angle determine เค•เคฐเคจे เค•े เคฒिเค।

Clinometer

Use: Slope angle เคฏा inclination measure เค•เคฐเคจे เค•े เคฒिเค।

Hand Level

Use: Approximate elevation difference เค”เคฐ gradient determine เค•เคฐเคจे เค•े เคฒिเค।

Important Instrument Comparison

Instrument Main Use Important Point
Chain Distance measurement Linear measurement
Prismatic Compass Magnetic bearing Whole Circle Bearing
Surveyor's Compass Magnetic bearing Quadrantal Bearing
Plane Table Field plotting Observation + plotting
Dumpy Level Elevation difference Levelling
Theodolite Horizontal & vertical angles Angular measurement
EDM Distance Electromagnetic waves
Total Station Angles + distance + coordinates Electronic instrument
GPS/GNSS Position & coordinates Satellite based
Optical Square Perpendicular offset 90° offset

Surveying Instruments – 50 MCQs

Instructions: เคธเคญी questions attempt เค•เคฐें เค”เคฐ เค…ंเคค เคฎें Submit Quiz เคฆเคฌाเคँ।

Frequently Asked Questions

Which instrument measures horizontal and vertical angles?

Theodolite.

Which instrument measures magnetic bearing?

Prismatic compass or Surveyor's compass.

Which instrument is used for determining difference in elevation?

Level with levelling staff.

Which instrument combines angle and distance measurement?

Total Station.

Which instrument is used for perpendicular offset?

Cross staff or Optical square.

Surveying Instruments & 50 MCQs | Civil Engineering Study Material

Surveying Curves MCQ Quiz – 50 Questions for Sub Engineer

Surveying Curves MCQ Quiz – 50 Questions for Sub Engineer

Surveying Curves MCQ Quiz – 50 Questions for Sub Engineer

Welcome to the comprehensive Surveying – Curves Practice Quiz tailored specifically for the MP Sub Engineer (Civil) competitive examination. Curves are an indispensable component of highway and railway alignment design, making this topic high-yield for engineering entrance and recruitment exams.

Quiz Structure & Rules:

  • Total Questions: 50 MCQs (Includes 20+ precise numerical calculation questions).
  • Difficulty Level: 20% Easy, 50% Moderate, and 30% Difficult (As per Sub Engineer pattern).
  • Marking Scheme: Correct Answer = +1 Mark, Wrong Answer = −0.25 Mark, Unattempted = 0 Mark.
  • Immediate Feedback: Click 'Check Answer' on any question to instantly verify your choice and view step-by-step solutions.
Live Score: 0.00 / 50
Correct: 0
Wrong: 0
Skipped: 50
Attempted: 0

Question Palette

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Q1. The angle of deflection ($\Delta$) of a simple circular curve is equal to which of the following angles at the center of the curve?
Q2. Calculate the tangent length ($T$) for a simple circular curve of radius $300\text{ m}$ having a deflection angle of $40^\circ$.
Q3. According to the $30\text{ m}$ arc definition, the degree of curve ($D$) and radius ($R$) are related by which exact expression?
Q4. Determine the length of long chord ($LC$) for a curve having a radius of $250\text{ m}$ and a central angle of $60^\circ$.
Q5. Mid-ordinate ($M$) of a simple circular curve of radius $R$ and deflection angle $\Delta$ is given by the formula:
Q6. Find the external distance ($E$) for a circular curve with $R = 400\text{ m}$ and deflection angle $\Delta = 30^\circ$.
Q7. If the chainage of the Point of Intersection (PI) is $1250.00\text{ m}$ and the tangent length is $145.20\text{ m}$, what is the chainage of the Point of Curve (PC)?
Q8. Calculate the length of a curve ($L$) having a radius of $350\text{ m}$ and deflection angle of $45^\circ$.
Q9. Rankine's method of deflection angles for setting out circular curves relies on which basic instrument combination?
Q10. Calculate the tangential angle $\delta$ (in minutes) for a chord length of $20\text{ m}$ and radius of $200\text{ m}$ using Rankine's formula.
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Q11. A reverse curve consists of two circular arcs bending in opposite directions. What is the main operational disadvantage of a reverse curve on high-speed highways?
Q12. What ideal geometric curve shape is most widely used as a transition curve in highway engineering in India?
Q13. For an ideal transition curve, the radius of curvature at any point is:
Q14. Compute the shift ($S$) of a circular curve of radius $300\text{ m}$ if a transition curve of length $60\text{ m}$ is introduced.
Q15. Calculate the degree of curve ($D$) for a radius of $573\text{ m}$ according to $20\text{ m}$ arc definition.
Q16. A compound curve consists of two circular arcs of radii $R_1 = 300\text{ m}$ and $R_2 = 500\text{ m}$. The deflection angles for the respective arcs are $\Delta_1 = 30^\circ$ and $\Delta_2 = 40^\circ$. Calculate the total length of the compound curve.
Q17. In setting out a curve by the method of offsets from long chord, the maximum offset ($x_0$) occurs at:
Q18. If the radius of a curve is $200\text{ m}$ and length of long chord is $160\text{ m}$, calculate the mid-ordinate offset ($O_0$) using the exact formula $O_0 = R - \sqrt{R^2 - (L/2)^2}$.
Q19. Calculate the length of a transition curve required for a design speed $v = 65\text{ km/h}$ on a curve of radius $R = 220\text{ m}$, assuming rate of change of centrifugal acceleration $C = 0.6\text{ m/s}^3$.
Q20. In two-theodolite method of curve setting, what is the main field operation advantage?
Q21. A $4^\circ$ curve is specified using standard $30\text{ m}$ arc definition. What is the radius of this curve?
Q22. In the chord deflection method (offsets from chords produced), the offset $O_1$ for the first sub-chord of length $c_1$ on a curve of radius $R$ is:
Q23. Compute the first offset ($O_1$) in chord deflection method if the initial sub-chord is $10\text{ m}$ and curve radius is $250\text{ m}$.
Q24. If the chainage of PC is $1000.00\text{ m}$ and curve length is $235.62\text{ m}$, what is the chainage of PT?
Q25. In highway survey, the point where a straight line (tangent) meets the circular curve is formally termed as:
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Q26. Compute the radial offset ($O_x$) at a distance $x = 20\text{ m}$ from the PC along the tangent, for a curve radius $R = 200\text{ m}$ (use exact expression $O_x = \sqrt{R^2 + x^2} - R$).
Q27. Using the approximate formula for radial offset ($O_x \approx \frac{x^2}{2R}$), compute the offset at distance $x = 30\text{ m}$ for $R = 300\text{ m}$.
Q28. A curve whose radius varies continuously from infinity at the tangent point to a finite value $R$ at the circular curve is called a:
Q29. Calculate the deflection angle $\Delta$ of a curve if the tangent length is equal to the radius of the curve ($T = R$).
Q30. A vertical curve is provided on highways to join two intersecting gradients. What geometric shape is generally adopted for vertical curves?
Q31. Calculate the length of a transition curve ($L_s$) required to introduce a full superelevation $e = 0.07$ on a $7\text{ m}$ wide road, if the rate of introduction of superelevation is 1 in 150 (outer edge raised relative to inner edge).
Q32. If the central angle of a circular curve is $90^\circ$, what is the ratio of its long chord length to its radius ($LC / R$)?
Q33. What is the apex distance (external distance $E$) of a curve when $R = 250\text{ m}$ and deflection angle $\Delta = 60^\circ$?
Q34. The total angle of deflection for setting out the $n$-th point on a curve using Rankine's method is $\Delta_n$. How is $\Delta_n$ related to individual tangential angles ($\delta_1, \delta_2, ... \delta_n$)?
Q35. Calculate the mid-ordinate ($M$) of a simple circular curve with radius $300\text{ m}$ and central angle $60^\circ$.
Q36. Where are reverse curves mostly preferred and permitted in civil engineering practice?
Q37. Find the chainage of PI if chainage of PC is $1450.00\text{ m}$ and tangent length is $125.50\text{ m}$.
Q38. A spiral transition curve has a length $L_s = 80\text{ m}$ and radius of circular arc $R = 200\text{ m}$. Calculate the total spiral angle ($\phi_s$) in radians.
Q39. Convert the spiral angle $\phi_s = 0.20\text{ rad}$ into degrees.
Q40. What is the relationship between the angle of deflection ($\alpha$) of a transition curve and its spiral angle ($\phi_s$)?
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Q41. Calculate the perpendicular offset from tangent to a circular curve of radius $R = 400\text{ m}$ at distance $x = 40\text{ m}$ using approximation $O_x = \frac{x^2}{2R}$.
Q42. The point of intersection of two tangents is called PI. If the back azimuth of initial tangent is $45^\circ$ and forward azimuth of next tangent is $105^\circ$, what is the deflection angle $\Delta$?
Q43. In the chord deflection method, the second offset $O_2$ for a normal chord $c_2$ following a sub-chord $c_1$ on a curve of radius $R$ is given by:
Q44. Calculate $O_2$ if $c_1 = 10\text{ m}$, $c_2 = 20\text{ m}$, and $R = 200\text{ m}$.
Q45. Bernoulli's Lemniscate transition curve is particularly suited for roads when the deflection angle is:
Q46. What is the fundamental purpose of providing superelevation (cant) along circular curves?
Q47. If the radius of a curve is reduced to half its original value while keeping speed constant, how does the centrifugal force change?
Q48. Calculate the length of long chord for a curve having $R = 150\text{ m}$ and deflection angle $\Delta = 90^\circ$.
Q49. In a simple circular curve, the angle subtended by a sub-chord of $15\text{ m}$ length at the center for $R = 300\text{ m}$ is:
Q50. The total length of a curve is $314.16\text{ m}$ and its radius is $200\text{ m}$. Calculate its central deflection angle $\Delta$ in degrees.

Important Surveying Curve Formulas

Keep these standard formulas handy for quick calculations in Civil Engineering competitive exams:

Element Standard Formula Key Notations
Tangent Length ($T$) $T = R \tan\left(\frac{\Delta}{2}\right)$ $R$ = Radius, $\Delta$ = Deflection Angle
Length of Curve ($L$) $L = \frac{\pi R \Delta}{180^\circ}$ $\Delta$ in degrees
Long Chord ($LC$) $LC = 2R \sin\left(\frac{\Delta}{2}\right)$ Distance between PC and PT
External Distance ($E$) $E = R \left[\sec\left(\frac{\Delta}{2}\right) - 1\right]$ Apex distance from PI to curve
Mid-Ordinate ($M$) $M = R \left[1 - \cos\left(\frac{\Delta}{2}\right)\right]$ Distance from mid-point of chord to curve
Degree of Curve ($D$) $R = \frac{1718.9}{D}$ ($30\text{ m}$ arc)
$R = \frac{1146}{D}$ ($20\text{ m}$ arc)
$D$ in degrees, $R$ in meters
Shift of Transition Curve ($S$) $S = \frac{L_s^2}{24 R}$ $L_s$ = Length of transition curve
Rankine's Tangential Angle ($\delta$) $\delta = 1718.9 \times \frac{c}{R} \text{ (minutes)}$ $c$ = chord length, $R$ = curve radius

Frequently Asked Questions (FAQs)

Q1. What is a Simple Circular Curve?
A simple circular curve consists of a single arc of constant radius connecting two straight tangents to provide a gradual change in direction.
Q2. What is Tangent Length in curve surveying?
Tangent length ($T$) is the distance from the Point of Intersection (PI) to the Point of Curve (PC) or Point of Tangency (PT). Calculated as $T = R \tan(\Delta/2)$.
Q3. What is the difference between Long Chord and Short Chord?
Long chord is the straight line joining the point of curve (PC) to the point of tangency (PT). Short chords (or sub-chords) are shorter line segments measured along the curve between individual pegs during layout.
Q4. Why is a Transition Curve provided on highways and railways?
Transition curves are provided to gradually introduce centrifugal force, superelevation (cant), and extra widening, preventing sudden shocks to vehicles and improving passenger comfort.
Q5. What is a Reverse Curve and where is it used?
A reverse curve consists of two circular arcs bending in opposite directions with a common tangent. It is primarily used in railway yards, sidings, and low-speed hilly roads where space is constrained.
Q6. How does negative marking work in this online quiz?
For every correct answer, +1 Mark is awarded. For every incorrect answer, 0.25 Mark is deducted. Unattempted questions carry zero penalty.

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